In C++, when an operator is given user-defined meaning, then it is called ____________
Which of the following operators can’t be overloaded in C++?
Correct way of declaring operator overloaded function in C++ is:-
What is the output of this C++ program?
#include <iostream>
using namespace std;
class sample
{
public:
int x, y;
sample() {};
sample(int, int);
sample operator + (sample);
};
sample::sample (int a, int b)
{
x = a;
y = b;
}
sample sample::operator+ (sample param)
{
sample temp;
temp.x = x + param.x;
temp.y = y + param.y;
return (temp);
}
int main ()
{
sample a (4,1);
sample b (3,2);
sample c;
c = a + b;
cout << c.x << "," << c.y;
return 0;
}
What is the output of this C++ program?
#include <iostream>
using namespace std;
class Box
{
double length;
double breadth;
double height;
public:
double getVolume(void)
{
return length * breadth * height;
}
void setLength( double len )
{
length = len;
}
void setBreadth( double bre )
{
breadth = bre;
}
void setHeight( double hei )
{
height = hei;
}
Box operator+(const Box& b)
{
Box box;
box.length = this->length + b.length;
box.breadth = this->breadth + b.breadth;
box.height = this->height + b.height;
return box;
}
};
int main( )
{
Box Box1;
Box Box2;
Box Box3;
double volume = 0.0;
Box1.setLength(6.0);
Box1.setBreadth(7.0);
Box1.setHeight(5.0);
Box2.setLength(12.0);
Box2.setBreadth(13.0);
Box2.setHeight(10.0);
volume = Box1.getVolume();
cout << "Volume of Box1 : " << volume <<endl;
volume = Box2.getVolume();
cout << "Volume of Box2 : " << volume <<endl;
Box3 = Box1 + Box2;
volume = Box3.getVolume();
cout << "Volume of Box3 : " << volume <<endl;
return 0;
}
What is the output of this C++ program?
#include <iostream>
using namespace std;
class Integer
{
int i;
public:
Integer(int ii) : i(ii) {}
const Integer
operator+(const Integer& rv) const
{
cout << "operator+" << endl;
return Integer(i + rv.i);
}
Integer&
operator+=(const Integer& rv)
{
cout << "operator+=" << endl;
i += rv.i;
return *this;
}
};
int main()
{
int i = 1, j = 2, k = 3;
k += i + j;
Integer ii(1), jj(2), kk(3);
kk += ii + jj;
}
What is the output of this program?
#include <iostream>
using namespace std;
class myclass
{
public:
int i;
myclass *operator->()
{return this;}
};
int main()
{
myclass ob;
ob->i = 10;
cout << ob.i << " " << ob->i;
return 0;
}
Which of the following statements is NOT valid about operator overloading?
Operator overloading in C++ is ____________
What is the output of this C++ program?
#include <iostream>
using namespace std;
ostream & operator<<(ostream & i, int n)
{
return i;
}
int main()
{
cout << 5 << endl;
cin.get();
return 0;
}
