github

Made bySaurav Hathi

ECE - Practice Test - 66

Q1:

For a test charge placed at infinity, the electric field will be

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q2:

In electromagnetic waves, the electric field will be perpendicular to which of the following?

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q3:

The potential difference in an open circuit is

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q4:

Find the current density of a material with resistivity 20 units and electric field intensity 2000 units.

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q5:

Find the potential due the dipole when the angle subtended by the two charges at the point P is perpendicular.

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q6:

Six equal point charges Q = 10nC are located at 2,3,4,5,6,7m. Find the potential at origin

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q7:

The potential due to the dipole on the midpoint of the two charges will be

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q8:

A point charge 0.4 nC is located at (2, 3, 3). Find the potential differences between (2, 3, 3)m and (-2, 3, 3)m due to the charge.

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q9:

Find the potential of V=60sinθr2 at P(3,60,25)

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q10:

Given E = 40xy i + 20x2 j + 2 k. Calculate the potential between two points (1,-1,0) and (2,1,3)

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q11:

The total charge of a surface with densities 1,2,…,10 is

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q12:

If the potential is given by, V=10sinθcos(φr), find the density at the point P(2,π/2,0)(in 10-12 units)

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q13:

A cable of core radius 1.25cm and impregnated paper insulation of thickness 2.13cm and relative permittivity 3.5. Compute the capacitance of the cable/km(in nF)

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q14:

Find the velocity of an electron when its kinetic energy is equal to one electron volt (in 105m/s). Given charge of an electron e = 1.6 x 10-19 and mass of an electron m = 9.1 x 10-31.

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options:
Q15:

Calculate the energy in an electric field with permittivity of 56 and field intensity of 36πJ(in μJ)

Tags:
PlaceMe2_EMFT1
Section:
Electromagnetics (EMFT)
Options: